Rayleigh Distribution with MLE Solution
This example validates the results for a Rayleigh distribution (1-parameter Weibull with beta = 2) in Weibull++ standard folios.
Reference Case
The data set is from Example 5.11 on page 283 in the book Reliability Engineering by Dr. Elsayed, Addison Wesley Longman, Inc, 1996.
Data
| State F/S | Time to F/S |
|---|---|
| F | 10 |
| F | 20 |
| F | 30 |
| F | 35 |
| F | 39 |
| F | 42 |
| F | 44 |
| S | 50 |
| S | 50 |
| S | 50 |
Result
- The model parameter is
- The Mean Life is 41.49
- The Standard Deviation is 21.70
Results in Weibull++
- The model parameter is:
- The mean life is:
- The standard deviation is:



